-2b^2+4b+5=7

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Solution for -2b^2+4b+5=7 equation: 



-2b^2+4b+5=7

We move all terms to the left:

-2b^2+4b+5-(7)=0

We add all the numbers together, and all the variables

-2b^2+4b-2=0

a = -2; b = 4; c = -2;
Δ = b2-4ac
Δ = 42-4·(-2)·(-2)
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{-4}{-4}=1$

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